Leetcode Problem:
Summary
- The problem requires finding the sum of all XOR totals for every subset of the given array.
Approach
- The approach used is a recursive function that tries all possible subsets by either including or excluding the current element in the subset.
Complexity
- O(2^n * n) where n is the number of elements in the array
Explanation
- The solution uses a recursive function to generate all possible subsets
- For each subset, it calculates the XOR total by XORing all elements in the subset
- The base case is when the current index is out of bounds, in which case the XOR total is added to the result
- The function is called recursively with the next index and the XOR total of the current element
- The time complexity is O(2^n * n) because in the worst case, we have to generate all possible subsets and calculate the XOR total for each subset.
Solution Code:
class Solution {
public:
int ans = 0;
void go(int cur, int sum, vector& nums){
if(cur >= nums.size()) {
ans += sum;
return;
}
go(cur + 1, sum ^ nums[cur], nums );
go(cur + 1, sum, nums );
}
int subsetXORSum(vector& nums) {
go(0, 0, nums);
return ans;
}
};